裂项相消万能公式有哪些

裂项相消的公式1/n(n+1)=1/n-1/(n+1)1/(2n-1)(2n+1)=1/2[1/(2n-1)-1/(2n+1)]1/n(n+1)(n+2)=1/2[1/n(n+1)-1/(n+1)(n+2)]1/(√daoa+√b)=[1/(a-b)](√a-√b)n·n!=(n+1)!-n